# GATE MT 2011 Q31. If K is the rate constant for a reaction and T is the absolute temperature in the given figure, and the activation energy for the reaction is:

Share

Have an account? Sign In Now

Need An Account, Sign Up Here

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

Askmemetallurgy Official

Asked: 2020-03-14T04:32:51+05:30
2020-03-14T04:32:51+05:30In: Thermodynamics & Rate Processes

28.57%(A) 1000 J/mol ( 2 voters )
0%(B) 2000 J/mol
0%(c) 4155 J/mol
71.43%(D) 8314 J/mol ( 5 voters )

Based On 7 Votes

Share

Leave an answer

Askmemetallurgy website uses cookies to improve your experience. Cookie settingsACCEPT

Privacy & Cookies Policy

This website uses cookies to improve your experience while you navigate through the website. Out of these cookies, the cookies that are categorized as necessary are stored on your browser as they are essential for the working of basic functionalities of the website. We also use third-party cookies that help us analyze and understand how you use this website. These cookies will be stored in your browser only with your consent. You also have the option to opt-out of these cookies. But opting out of some of these cookies may have an effect on your browsing experience.

take ln in the equation and find the slope.

take ln in the equation and find the slope.

See lessCorrect answer is option D. Using K = A exp(-Q/RT) ln k = ln A - Q/RT -8 = ln A - Q/R × 10-3 -9 = ln A -Q/R × 2 × 10-3 On simplification, Q/R = 10-3 Q= 8314 J/mol

Correct answer is option D.

Using K = A exp(-Q/RT)

ln k = ln A – Q/RT

-8 = ln A – Q/R × 10

^{-3}-9 = ln A -Q/R × 2 × 10

^{-3}On simplification, Q/R = 10

^{-3}Q= 8314 J/mol

See less